b^2-21b+121=b

Solution for b^2-21b+121=b equation:

Simplifying
b2 + -21b + 121 = b

Reorder the terms:
121 + -21b + b2 = b

Solving
121 + -21b + b2 = b

Solving for variable 'b'.

Reorder the terms:
121 + -21b + -1b + b2 = b + -1b

Combine like terms: -21b + -1b = -22b
121 + -22b + b2 = b + -1b

Combine like terms: b + -1b = 0
121 + -22b + b2 = 0

Factor a trinomial.
(11 + -1b)(11 + -1b) = 0

Subproblem 1
Set the factor '(11 + -1b)' equal to zero and attempt to solve:

Simplifying
11 + -1b = 0

Solving
11 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + -1b = 0 + -11

Combine like terms: 11 + -11 = 0
0 + -1b = 0 + -11
-1b = 0 + -11

Combine like terms: 0 + -11 = -11
-1b = -11

Divide each side by '-1'.
b = 11

Simplifying
b = 11
Subproblem 2
Set the factor '(11 + -1b)' equal to zero and attempt to solve:

Simplifying
11 + -1b = 0

Solving
11 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + -1b = 0 + -11

Combine like terms: 11 + -11 = 0
0 + -1b = 0 + -11
-1b = 0 + -11

Combine like terms: 0 + -11 = -11
-1b = -11

Divide each side by '-1'.
b = 11

Simplifying
b = 11
Solution
b = {11, 11}